Showing posts with label Computer. Show all posts
Showing posts with label Computer. Show all posts

Thursday 14 August 2014

TCS CodeVita 2014 and its Importance for Current BE Students

Posted by Suhel Sayyad
 Tata Consultancy Services (TCS), a leading IT services, consulting and business solutions organization, announced that it is hosting TCS CodeVita, a contest for engineering and science students to experience the joy of coding and to sharpen their programming skills through real-life computing practices. The contest also aims at identifying the talent, besides providing the student community, an opportunity to earn peer recognition. TCS is promoting learning through fun and contests like CodeVita as programming is becoming the skill for future and provide a fast gateway to technology career.

TCS CodeVita 2014 and its Importance for Current BE Students


CodeVita will be held in two phases based on the annual academic calendar. In phase 1, students from Mexico, Colombia, Uruguay, Peru, Australia, South Africa and India can register during July-August. While in phase 2, students from Canada, UK, China, Singapore and Japan can register in October.

CodeVita is a two member team contest and involves three rounds of coding. Each member has to register individually on the CodeVita portal. CodeVita contest supports coding in 7 languages – Java, C#, C, Perl, C++, Python and Ruby.
Ajoy Mukherjee, Executive Vice President said: “Coding is a mind sport. Programming skills helps engineering students to solve complex problems and promotes conceptual thinking as it blends mathematics, logic and alogrithms.”

The contest comprises three rounds:
  • Round 1: Programming problem statements.
  • Round 2: Top 5% of teams from Phase I countries will move into this round.
  • Grand Finale: Top 15 teams from both Phase 1 and Phase 2 geographies from round 2 will be invited for the Grand Finale. Top 3 teams will be declared winners of the contest.

Winning teams will be judged based on accuracy, speed and efficiency. To avoid plagiarism and to promote the best practices, CodeVita this year has introduced the gamification element to differentiate the low, average and high performers based on time element and ranking. Converting a ‘Time advantage’ into a ‘Score advantage’ provides benefits such as using time as a currency to earn scores and thus, gamify problem solving and since time continuously changes, plagiarism will be less effective.
The Winners will receive exciting prizes, internship offers with CTO Team and provisional Offer Letters from TCS.

TCS has been actively involved in engaging students across campuses as part of its Academic Interface Programme. Through “Campus Commune” a dedicated social engagement platform which has over 300,000 student members, TCS encourages learning through discussion and interaction with other students present on the online community, as well as the TCS employees who are open to providing mentorship. The forum is extensively used to spot talent through various engagement programme as well as contests such as CodeVita, Mobeel, Testimony, EngiNX, etc. It is also used as a platform to stay connected with prospective employees throughout the academic life cycle of a student.
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Sunday 10 August 2014

Aptitude Questions Helpful for Tata Consultancy Services (TCS) 2014-15 Recruitment

Posted by Suhel Sayyad
1) A power unit is there by the bank of a river of 900 meters. A cable is made from power unit to power a plant opposite to that of the river of 2000mts. The cost of the cable below water is Rs. 5/- per meter and cost of cable on the bank is Rs. 4/- per meter. Then find out the amount to be invested to connect those two stations?
Explanation:
Required length of wire = 2000 mts cost of cable below water = 900 * 5 = 4500 cost of cable on the bank of river= (2000 - 900) * 4 = 4400 Total cost = 4500 + 4400 = 8900.

2) A farmer had 20 hens. All but 2 died. How many hens are still alive?
Explanation:
"All but 2" means 2. So, all but 2 died means that there are only two hens are alive and others were dead. So, the answer is 2.


3) At this series: 7, 10, 8, 11, 9, 12... What number should come next?
Explanation:
This is a simple alternating addition and subtraction series. In the first pattern, 3 are added; in the second, 2 are subtracted.

4) A college has 10 basketball players. A 5-member team and a captain will be selected out of these 10 players. How many different selections can be made?

Explanation:
We can select the 5 member team out of the 10 in 10C5 ways = 252 ways. The captain can be selected from amongst the remaining 5 players in 5 ways. Therefore, total ways the selection of 5 players and a captain can be made = 252*5 = 1260.

5) There are 3 gentlemen in a meeting: Mr. Yellow, Mr. Green and Mr. Brown. They are wearing yellow, green and brown ties. Mr. Yellow says: "Did you notice that the colors of our ties are different from our names?" The person who is wearing the green tie says, "Yes, you are right!" Do you know Brown is wearing what colour of tie?
Explanation:
We know that Mr. Yellow was not wearing a yellow tie because of his statement. He also was not wearing the green tie because the one wearing the green tie agreed to his statement. Therefore, Mr. Yellow was wearing a brown tie. Mr. Green was wearing a yellow tie. And Mr. Brown was wearing the green tie.

6) g[0]=1,g[1]=-1,g[n]=2*g[n-1]-3*g[n-2] then calculate g[4]= ?
Explanation:
From the given function g[n] =2*g [n-1]-3*g [n-2] put values of n as first 2 then 3, then 4 and you will get the answer. G[2] = 2*g[1]-3*g[0]=-2-3 =-5 , G[3]=2*g[2]-3*g[1] =2*(-5)-3*(-1)=-7, G [4] =2*g[3]-3*g[2]=2*(-7)-3*(-5) =1

7) Ten years ago X was half of Y. If the ratio of their present ages is 3:4, what will be the total of their present ages?
Explanation:
Let X's age 10 years ago = x years. Then, Y's age 10 years ago = 2x years. (x + 10)/ (2x + 10) = 3/4 => 4 (x + 10) = 3 (2x + 10) x = 5 Total of their present ages = (x + 10 + 2x + 10) = 3x + 20 = 15 + 20 = 35 years.

8) A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: 120KMPH

9) In a circular racetrack of length 100 m, three persons A, B and C start together. A and B start in the same direction at speeds of 10 m/s and 8 m/s respectively. While C runs in the opposite at 15 m/s. When will all the three meet for the first time after the start?
Explanation:
Since the track is a circular track A and B will meet every 50 seconds. i.e. 100 / (10-8). Since it is a multiple of 50 they will be meeting at the starting point every 50 Seconds. If you multiply 15 x 50 you will get 750 and after the second 50 it will be 1500. All of them will meet at the starting point after 100s

10) A class of 100 students. 24 of them are girls and 32 are not. Which base am I using?
Explanation:
Let the base be X. Therefore (X*X + X*0 + 0) = (2*X +4) + (3*X + 2), X * X = 5 * X + 6, X * X - 5 * X -6 = 0, (X- 6) (X+1) = 0 Therefore base is 6.


11) Siva, Sathish, Amar and Praveen are playing cards. Amar is to the right of Sathish, who is to the right of Siva. Who is to the right of Amar?
Answer: Praveen

12) Ferrari is leading car manufacturer. Ferrari S.P.A. is an Italian sports car. It has enjoyed great success. If Mohan's Ferrari is 3 times faster than his old MERCEDES which gave him 35 km/ph if Mohan travelled 490 km in his Ferrari the how much time in hours he took?

Explanation:
Time = (Distance/Speed) = (490/35) Therefore the total time = time/3 = (490/35)/3 = 4.6666 Approximately 4.7

13) My flight takes off at 2 AM from a place at 18N 10E and landed 10 Hrs later at a place with coordinates 36N 70W. What is the local time when my plane landed?
Explanation:
Total change in degrees in east-west direction = 70 + 10 degrees =80 degrees, Time change due to the change in Longitude = 80*4 = 320 minutes = 5 hrs 20 min. According to the person the time would have been = 2 am + 10 hrs = 12 am. But according to the local time the time would be = 12 - 5.20 = 6 .40am

14) A class of 25 students took a science test. 10 students had an average (arithmetic mean) score of 80. The other students had an average score of 60. What is the average score of the whole class?
Explanation:
80 × 10 + 60 × 15 = 800 + 900 = 1700 Total number of students = 25 Average weight = 1700/25 The average score of the whole class is 68.

15) The cost of one pencil, two pens and four erasers is Rs.22 while the cost of five pencils, four pens and two erasers is Rs.32. How much will three pencils, three pens and three erasers cost?

Explanation:
x + 2y + 4z = 22 -------->1 5x + 4y + 2z = 32 ------->2 multiply eqn (2) by 2 and substract from eqn(1) dividing by 3 we get 3x + 2y = 14--------->3 multiplying eqn (1) by 5 and subtracting eqn (2) then divide by 6 we get y + 3z = 13---------->4 Adding eqn (3) and (4) we get 3x + 3y +3z = 27

16) A is 20 percent more efficient than B. If the two persons can complete a piece of work in 60 days. In how many days A working alone can complete the work?
Explanation:
Ratio of time taken by A and B is 1: 1.2 i.e. 5:6 Let the time taken by A be 5x and by B be 6x , 1/5x + 1/ 6x = 1/60 => x =22. Time taken by A = 5 * 22 = 110

17) On a certain island, 5% of the 10000 inhabitants are one-legged and half of the others go barefooted. What is the least number of Shoes needed in the island?
Explanation:
In any case the one legged people will all require one shoe per head. From the remaining, half will go barefooted and therefore they need no shoes. And the rest will need two shoes per head. And this works out at one shoe per person for the others. Therefore for the whole population on the average one shoe per head

18) Look at this series: 14, 28, 20, 40, 32, 64, what number should come next?
Explanation:
This is an alternating multiplication and subtracting series: First, multiply by 2 and then subtract 8.

19) Two pipes A and B can fill a tank in 24 min. and 32 min. respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 minutes?
Explanation:
Let B be closed after x minutes. Then, part filled by (A + B) in x min. + part filled by an in (18 - x) min. = 1. X {1/24 + 1/32] + (18 - x) X 1/24 = 1 or 7x/96 + (18 - x)/24 = 1 7x + 4(18 -x) = 96 or x=8 Hence, B must be closed after 8 minutes

20) At a car park there are 100 vehicles, 60 of which are cars, 30 are vans and the remaining are Lorries. If every vehicle is equally likely to leave, find the probability of car leaving second if either a lorry or van had left first :
Explanation:
Let S be the sample space and A be the event of a van leaving first. n(S) = 100 n (A) = 30 Probability of a van leaving first: P (A) = 30/100 = 3/10 Let B be the event of a lorry leaving first. n (B) = 100 - 60 - 30 = 10 Probability of a lorry leaving first: P (B) = 10/100 = 1/10 If either a lorry or van had left first, then there would be 99 vehicles remaining, 60 of which are cars. Let T be the sample space and C be the event of a car leaving. n (T) = 99 n(C) = 60 Probability of a car leaving after a lorry or van has left: P(C) = 60/99 = 20/33


21) A red house is built from red bricks. A blue house is built from blue bricks. A white house is built from white bricks. Then what is a greenhouse made from?
Explanation:
Glass i.e. Buildings are made of bricks. But a greenhouse is made of glass.

22) If Rs. 782 be divided into three parts, proportional to 1/2: 2/3: 3/4, then the first part is: www.allindiajobs.in
Explanation:
Given ratio = 1/2: 2/3:3/4 = 6: 8: 9 1st part = 782*(6/22) = 213.2727.. Approximately equals to 213 www.allindiaobs.in


23) A man decides to buy a nice horse. He pays $60 for it, and he is very content with the strong animal. After a year, the value of the horse has increased to $70 and he decides to sell the horse . But after a few days later he regrets his decision to sell the beautiful horse, and he buys it again. Unfortunately he has to pay $80 to get it back, so he loses $10. After another year of owing the horse, he finally decides to sell the horse for $90. What is the overall profit the man makes?
Explanation:
The total expenses are $60 + $80 = $140 and the total earnings are $70 +$90 = $160. The overall profit = $160 - $140 = $ 20

24) When I become as old as my father is now, I will be 5 times the age of my son. In addition, my son will be 8 yrs older than What I am now. If the sum of my father's age and my age is equal to100. How old is my son now?
Explanation:
Let us consider the ages of the man, his father & his son is m, f & s respectively. Then according to the problem F=5s............ (i) S + f-m = m+8........ (ii) F + m = 100........... (iii) Putting (i) in (iii) we get 5s+m=100........ (iv) Putting (i) in (ii) we get 6s-2m=8............ (v) Equating (iv) & (v) we get s = 13, f = 65 & m = 36

25) Nine persons went to the hostel for taking their meals, 8 of them spent Rs.12 each on their meals and ninth spend Rs. 8 more then the average expenditure of all nine. What is the total money spent by them?
Explanation:
Let average expenditure be x Then 8*12 +(x+8) = 9x i.e. 104 + x = 9x; 8x = 104 x = 13 Therefore total money spent is 9x = 9*13 =117

26) The average of a list of 6 numbers is 20. If we remove one of the numbers, the average of the remaining numbers is 15. What is the number that was removed?

Explanation:
The removed number could be obtained by difference between the sum of original 6 numbers and the sum of remaining 5 numbers i.e. sum of original 6 numbers - sum of remaining 5 numbers sum of original 6 numbers = 20 × 6 = 120 sum of remaining 5 numbers = 15 × 5 = 75 Number removed = sum of original 6 numbers - sum of remaining 5 numbers 120 - 75 = 45

27) In the word ORGANISATIONAL, if the first and second, third and fourth, fifth and sixth letters are interchanged, what would be the 12th letter from right?
Explanation:
After interchanging R O A G I N S A T I O N A L 14 13 12 11 10 9 8 7 6 5 4 3 2 1

28) What are the number of edges, number of vertices and number of faces of a planar cube among the following options?
We know cube has 6 faces, 12 edges and 8 vertices

29 How many alphabets need to be there in a language if one were to make 1 million distinct 3 digit initials using the alphabets of the language?

Explanation:
Let the number of required alphabets in the language be 'n'. Therefore, using 'n' alphabets we can form n * n * n = n3 distinct 3 digit initials. These n3 different initials = 1 million i.e. n3 = 106 (1 million = 106) => n3 = (102)3 => n = 102 = 100

30) Today's high school students spend too much time thinking about trivial and distracting matters such as fashion. Additionally, they often dress inappropriately on school grounds. Rather than spending time writing another detailed dress policy, we should make school uniforms mandatory. If students were required to wear uniforms, it would increase a sense of community and harmony in our schools and it would instill a sense of discipline in our students. Another positive effect would be that teachers and administrators would no longer have to act as clothing police, freeing them up to focus on more important issues.
This paragraph best supports the statement that
Options:
a) inappropriate clothing leads to failing grades
b) students who wear school uniforms get into better colleges
c) teachers and administrators spend at least 25% of their time enforcing the dress code.
d) school uniforms should be compulsory for high school students
Answer: Explanation:
The support for choice e is in the third sentence "we should make school uniforms mandatory". There is no evidence provided to support choices a, b, and d. And although we know that teachers and administrators are spending some of their time enforcing dress code, the paragraph does not quantify how much of their time is spent that way, so there is no support for choice c.
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Thursday 12 September 2013

TCS Touchstone Test Pattern

Posted by Suhel Sayyad 9 Comments
The TouchStone Test will test your ability to demonstrate

•English Writing Skills

•Understanding of basic Mathematics concepts

•Logical reasoning

2 sections in the test:

Section 1: English writing skills

Section 2: Mathematics and Logical reasoning

Section 1

This section will consist of a task of writing a note / letter / email / paragraph.

What is given

–Situation

–Key Phrases that need to be used

–Minimum word-limit

–10min (countdown timer)

Task

–Using the key phrases the required write-up needs to be created for the given situation

Expectations

–Write-up to be grammatically correct

–Write-up should adhere to minimum word-limit mentioned

–Write-up to be such that intended message reaches the intended recipient

–Emphasis to be given on correct sentence construction

Section 2

•This section majorly consists of Multiple Choice Questions based on mathematics (class 1 to class 10 concepts) and logical reasoning

•You may expect Puzzles, SUDOKU, Crossword, diagram based questions, etcas well

•Allotted time: Around 80mins

•Countdown-timer will be present on the test screen, the timer starts once you see the 1stquestion

•Negative marking: One-third / 33%

•Questions-navigator will be present on the test screen, you may click on a question number and go to a particular question

Section 2

•Questions carrying higher weightage will be marked with a Blue Star. All Blue Starred questions carry equal weightage.

•Some questions may be long and descriptive

•Some questions may seem repeated, read through them very carefully, they might be similar, but they are not same

•Please keep on saving your answers in this section, you may come back to a question and change answers as well

•The test has in-built calculator on the test-screen, no physical calculators allowed inside the test room

•No mobile-phones allowed in the test room

Sample Topics / Concepts

TouchStone will test your understanding of Application of basic concepts like

•Ratios and Averages

•Basic Logic –AND, OR, NOT, etc

•Simultaneous linear equations

•Permutations and combinations

•Probability

•Statistics

•Compound Interest , Simple Interest

•Arithmetic and Geometric Progression

•Mensuration

•Trigonometry

•Geometry

•Quadratic Equations

•Number system
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Saturday 24 August 2013

Sonata Software Limited – Spring MVC Developers Positions 2013 – Bangalore

Posted by Suhel Sayyad
10 Vacancies at Sonata Software Limited for B.E/B.Tech/M.E/M.Tech. candidates. Apply Before 30th August, 2013
Name of the Government Organization: Sonata Software Limited
Sonata Software Limited invites applications for the following posts:
Job Designation: Spring MVC Developers
Number of Positions: 10 (Ten)
Educational Qualification: BE/ BTech / ME/ MTech / MCA / Any degree
Location of Posting: Bangalore
How To Apply: Interested candidates can sent their bio-data resume at the marynancy.r@sonata-software.com
Last Date To Apply: 30th August, 2013
Contact Address: APS Trust Building, Bull Temple Road, N. R. Colony, Bangalore – 560 019, India
Contact Numbers: 91-80-3097 1999, Fax: 91-80-2661 0972
Email: marynancy.r@sonata-software.com
Advertisement Details: http://www.sonata-software.com/web/sonata_en/careers/jobdetails.html?jobcode=A9&jobid=289
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Wednesday 17 July 2013

DRDO Recruitment 2013

Posted by Suhel Sayyad

DRDO Recruitment 2013

Name : DRDO Recruitment 2013

Qualification: Candidates should possess Degree in Library & Information Science for S.No 1 Discipline, Diploma in Library Science (Two Years) for S.No 2 Discipline & Degree in Computer Science (B.Tech only) for S.No 3 Discipline, with 60% or above marks.

Vacancy Details:
Total No. of Posts: 30
Name of the Post: Apprentice
Name of Disciplines:
1. Library & Information Science: 08 posts
2. Library Science: 06 posts
3. Computer Science: 16 posts

Selection process: Candidates will be selected based on their performance in interview.

How to Apply: Interested and eligible candidates may attend for interview along with Bio-Data giving complete personal detail, qualification and experience etc, two passport size photographs, all original documents and attested photocopies of all the certificates for verification from 05-08-2013 to 08-08-2013 at 09:00 AM at DESIDOC.

Interview Dates:
For Library & Information Science: 05-08-2013
For Library Science: 06-08-2013
For Computer Science: 07, 08-08-2013
Interview Time: 09:00 AM
Venue: DESIDOC


For More Details : Click Here
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Tuesday 16 July 2013

Project Assistant/Technical Assistant Posts 2013 – IMS – Chennai

Posted by Suhel Sayyad
7 Vacancies at Institute of Mathematical Sciences with pay scale RS.15000-16000 for B.E/B.Tech/M.Sc. candidates. Apply Before 19th July, 2013
Name of the Government Organization: Institute of Mathematical Sciences
Institute of Mathematical Sciences invites applications for the following posts:
Job Number: 01
Job Designation: Project Assistant
Number of Position: 01 (One)
Name of Project: IMSc Complex Systems
Educational Qualification: B.E/B.Tech/M.Sc from a reputed Institute with a good background either in physical/mathematical sciences or engineering or in biology, have some experience in using analytical & computational techniques, and have a strong interest in biological systems. Knowledge of MATLAB or equivalent scientific software is desirable.
Pay Scale: Rs. 16,000/- p.m. + HRA @ 30% on Consolidated Salary.
Job Number: 02
Job Designation: Project Assistant
Number of Position: 01 (One)
Name of Project: Project: Computer Modelling and Analysis of Economic/Financial Data & Networks
Educational Qualification: B.E./B.Tech/M.Sc from a reputed institution with a good background either in physical / mathematical sciences or engineering, have some experience in using analytical & computational techniques. Knowledge of MATLAB or equivalent scientific software is desirable.
Pay Scale: Rs. 16,000/- p.m. + HRA @ 30% on Consolidated Salary.
Job Number: 03
Job Designation: Project Assistant
Number of Position: 02 (Two)
Name of Project: Project: Trust Areas in Theoretical Physics “High Energy Physics Phenomenology Group”
Educational Qualification: M.Sc [Physics] or B.Tech/M.Tech in Electrical/Electronics Engineering or Computer Science Engineering with interest in particle physics.
Pay Scale: Rs. 16,000/- p.m. + HRA @ 30% on Consolidated Salary.
Job Number: 04
Job Designation: Project Assistant (House Keeping)
Number of Position: 01 (One)
Name of Project: Project: Administrative Project
Educational Qualification: Three year Degree (or) Diploma course in Hotel Management & Catering Technology from a reputed college / institution with minimum of 55% marks [after plus two]. Atleast 5 years in the field of House Keeping management with familiarity in computers, customer care, cleaning of various surfaces with good communication skills.
Pay Scale: Rs.15,000/- p.m. + HRA @ 30% on Consolidated Salary.
Job Number: 05
Job Designation: Technical Assistant [Civil]
Number of Position: 01 (One)
Name of Project: Project: Administrative Project
Educational Qualification: Diploma in Civil Engineering from a reputed college /institution with minimum of 55% marks. (3 years after SSC) approved by AICTE, New Delhi. Atleast 5 years experience in construction / maintenance of residential / commercial multistoried building, water supply and drainage systems including good knowledge of preparation of estimates and handling of contracts. He/she needs to assist the Civil Engineer in his/her day to day works.
Pay Scale: Rs.15,000/- p.m. + HRA @ 30% on Consolidated Salary.
Job Number: 06
Job Designation: Technical Assistant [Electrical]
Number of Position: 01 (One)
Name of Project: Project: Administrative Project
Educational Qualification: Diploma / Licentiate in Electrical Engineering with minimum of 55% marks from a reputed college / institution (3 years after SSC) approved by AICTE, New Delhi. Atleast 5 years experience with Electrical Supervisor Competency Certificate (`C’ Licence Holder) involved with following electrical field of 11 KV / 433V Electrical sub-station, 250 KVA and 62.5 KVA DG Sets and its automation, 680 Kg capacity electrical lifts, operation and maintenance of various ductable A/c Systems, Cooling Towers, networking, UPS and telecommunication system etc. He/she needs to assist the Electrical Engineer in his/her day to day works.
Pay Scale: Rs.15,000/- p.m. + HRA @ 30% on Consolidated Salary.
Location of Posting: Chennai
How To Apply: Interested candidates are requested to send their applications only through unique e-mail id as per details given below and mentioning the position details in the Subject e-mail as “Application for the Position of ……..Code No………” with a brief email content besides attaching their latest resume by 1700 hrs on July 19, 2013
Last Date To Apply: 19th July, 2013
Contact Address: Institute of Mathematical Sciences, (Autonomous Institution under DAE, Govt. of India), IV Cross Road, CIT Campus, Taramani, Chennai 600 113, Tamil Nadu, India.
Contact Numbers: 91-44-22543100 / Fax : 91-44-22541586
Advertisement Details: www.imsc.res.in/~office/jobs/advtpatajul2013.pdf
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Saturday 13 July 2013

Computer Engineer Post 2013 – Indian Institute of Technology, Bombay

Posted by Suhel Sayyad
1 Vacancy 2013 at Indian Institute of Technology with pay scale Rs.15600-39100 for B.E/B.Tech. candidates. Apply Before 29th July, 2013
Name of the Government Organization: Indian Institute of Technology
Indian Institute of Technology invites applications for the following posts:
Job Designation: Computer Engineer
Number of Positions: 01 (One) (UR-01)
Educational Qualification: B.Tech. or B.E. in Computer Science/Electrical Engg.,/Electronics Engg., or M.Sc. in Physics / Mathematics / Computer Science, or MCA; and two years work experience. M.Tech. in Computer Science/Electrical Engg./Electronics. A relevant, equivalent, recognized, other specialized Bachelors/Masters degree (with adequate experience).
Pay Scale: PB­3 (Rs.15600-39100) +  Rs.5400 (Grade Pay) Total emoluments on the minimum of Pay Band is Approx. Rs. 43,560/­ excluding HRA.
Age Limit: Preferably below 40 years.
Location of Posting: Mumbai
How To Apply: Candidates possessing the requisite qualification and experience may apply in prescribed format along with copies of certificates to The Registrar, IIT Bombay, Powai, Mumbai – 400076 on or before 29th July, 2013.
Last Date To Apply: 29th July, 2013
Contact Address: The Registrar, Indian Institute of Technology Bombay, Powai, Mumbai – 400076
Contact Numbers: 91-22-2572-2545 / FAX: +91-22-2572-3480
Advertisement Details: http://www.iitb.ac.in/CEAdvt2013.pdf
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